Hello,
With the following table how would I create a query that would return all
rows whos EndDate minus StartDate is more than 28 Days.
TableName: Customers
ID - Integer
CustomerID - VarChar
StartDate - Date
EndDate - Date
Table:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
2 Mike1 8/25/06 9/15/06
3 Dinah 8/23/06 9/1/06
4 James 7/11/06 8/30/06
The Query Should Return:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
4 James 7/11/06 8/30/06
Thanks,
Chuck
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> Table:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
> The Query Should Return:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
> Thanks,
> Chuck
>
|||Thank You
Chuck
"Arnie Rowland" <arnie@.1568.com> wrote in message
news:uHoF7yQ2GHA.3656@.TK2MSFTNGP04.phx.gbl...
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message
news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> Table:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
> The Query Should Return:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
> Thanks,
> Chuck
>
Showing posts with label whos. Show all posts
Showing posts with label whos. Show all posts
Friday, March 30, 2012
Help With SQL Query
Hello,
With the following table how would I create a query that would return all
rows whos EndDate minus StartDate is more than 28 Days.
TableName: Customers
ID - Integer
CustomerID - VarChar
StartDate - Date
EndDate - Date
Table:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
2 Mike1 8/25/06 9/15/06
3 Dinah 8/23/06 9/1/06
4 James 7/11/06 8/30/06
The Query Should Return:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
4 James 7/11/06 8/30/06
Thanks,
ChuckSELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
--
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message news:O6E$smQ2GHA.5048@.T
K2MSFTNGP05.phx.gbl...
> Hello,
>
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
>
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
>
> Table:
>
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
>
> The Query Should Return:
>
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
>
> Thanks,
>
> Chuck
>
>|||Thank You
Chuck
"Arnie Rowland" <arnie@.1568.com> wrote in message
news:uHoF7yQ2GHA.3656@.TK2MSFTNGP04.phx.gbl...
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message
news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> Table:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
> The Query Should Return:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
> Thanks,
> Chuck
>
With the following table how would I create a query that would return all
rows whos EndDate minus StartDate is more than 28 Days.
TableName: Customers
ID - Integer
CustomerID - VarChar
StartDate - Date
EndDate - Date
Table:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
2 Mike1 8/25/06 9/15/06
3 Dinah 8/23/06 9/1/06
4 James 7/11/06 8/30/06
The Query Should Return:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
4 James 7/11/06 8/30/06
Thanks,
ChuckSELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
--
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message news:O6E$smQ2GHA.5048@.T
K2MSFTNGP05.phx.gbl...
> Hello,
>
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
>
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
>
> Table:
>
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
>
> The Query Should Return:
>
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
>
> Thanks,
>
> Chuck
>
>|||Thank You
Chuck
"Arnie Rowland" <arnie@.1568.com> wrote in message
news:uHoF7yQ2GHA.3656@.TK2MSFTNGP04.phx.gbl...
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message
news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> Table:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
> The Query Should Return:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
> Thanks,
> Chuck
>
Help With SQL Query
Hello,
With the following table how would I create a query that would return all
rows whos EndDate minus StartDate is more than 28 Days.
TableName: Customers
ID - Integer
CustomerID - VarChar
StartDate - Date
EndDate - Date
Table:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
2 Mike1 8/25/06 9/15/06
3 Dinah 8/23/06 9/1/06
4 James 7/11/06 8/30/06
The Query Should Return:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
4 James 7/11/06 8/30/06
Thanks,
ChuckThis is a multi-part message in MIME format.
--=_NextPart_000_086D_01C6D8D2.0BEDBF60
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
-- Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience. Most experience comes from bad judgment. - Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message =news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> > With the following table how would I create a query that would return =all > rows whos EndDate minus StartDate is more than 28 Days.
> > TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> > Table:
> > ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
> > > The Query Should Return:
> > ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
> > > Thanks,
> > Chuck > >
--=_NextPart_000_086D_01C6D8D2.0BEDBF60
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
&
SELECT
=ID
, =CustomerID
, =StartDate
, =EndDate
FROM Customers
WHERE datediff( day, StartDate, =EndDate ) > 28
-- Arnie Rowland, =Ph.D.Westwood Consulting, Inc
Most good judgment comes from =experience. Most experience comes from bad judgment. - Anonymous
"Charles A. Lackman" wrote in message news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...> =Hello,> > With the following table how would I create a query that would =return all > rows whos EndDate minus StartDate is more than 28 =Days.> > TableName: Customers> ID - Integer> CustomerID - VarChar> StartDate - Date> EndDate - Date> > =Table:> > ID CustomerID StartDate EndDate> 1 Chuck1 &=nbsp; 9/1/06 =9/30/06> 2 Mike1 &n=bsp; 8/25/06 =9/15/06> 3 Dinah &n=bsp; 8/23/06 9/1/06> 4 James &n=bsp; 7/11/06 8/30/06> > > The Query Should Return:> => ID CustomerID StartDate EndDate> 1 Chuck1 &=nbsp; 9/1/06 =9/30/06> 4 James &n=bsp; 7/11/06 8/30/06> > > Thanks,> > Chuck => >
--=_NextPart_000_086D_01C6D8D2.0BEDBF60--|||Thank You
Chuck
"Arnie Rowland" <arnie@.1568.com> wrote in message
news:uHoF7yQ2GHA.3656@.TK2MSFTNGP04.phx.gbl...
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
--
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message
news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> Table:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
> The Query Should Return:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
> Thanks,
> Chuck
>sql
With the following table how would I create a query that would return all
rows whos EndDate minus StartDate is more than 28 Days.
TableName: Customers
ID - Integer
CustomerID - VarChar
StartDate - Date
EndDate - Date
Table:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
2 Mike1 8/25/06 9/15/06
3 Dinah 8/23/06 9/1/06
4 James 7/11/06 8/30/06
The Query Should Return:
ID CustomerID StartDate EndDate
1 Chuck1 9/1/06 9/30/06
4 James 7/11/06 8/30/06
Thanks,
ChuckThis is a multi-part message in MIME format.
--=_NextPart_000_086D_01C6D8D2.0BEDBF60
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
-- Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience. Most experience comes from bad judgment. - Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message =news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> > With the following table how would I create a query that would return =all > rows whos EndDate minus StartDate is more than 28 Days.
> > TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> > Table:
> > ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
> > > The Query Should Return:
> > ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
> > > Thanks,
> > Chuck > >
--=_NextPart_000_086D_01C6D8D2.0BEDBF60
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
&
SELECT
=ID
, =CustomerID
, =StartDate
, =EndDate
FROM Customers
WHERE datediff( day, StartDate, =EndDate ) > 28
-- Arnie Rowland, =Ph.D.Westwood Consulting, Inc
Most good judgment comes from =experience. Most experience comes from bad judgment. - Anonymous
"Charles A. Lackman"
--=_NextPart_000_086D_01C6D8D2.0BEDBF60--|||Thank You
Chuck
"Arnie Rowland" <arnie@.1568.com> wrote in message
news:uHoF7yQ2GHA.3656@.TK2MSFTNGP04.phx.gbl...
SELECT
ID
, CustomerID
, StartDate
, EndDate
FROM Customers
WHERE datediff( day, StartDate, EndDate ) > 28
--
Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience.
Most experience comes from bad judgment.
- Anonymous
"Charles A. Lackman" <Charles@.CreateItSoftware.net> wrote in message
news:O6E$smQ2GHA.5048@.TK2MSFTNGP05.phx.gbl...
> Hello,
> With the following table how would I create a query that would return all
> rows whos EndDate minus StartDate is more than 28 Days.
> TableName: Customers
> ID - Integer
> CustomerID - VarChar
> StartDate - Date
> EndDate - Date
> Table:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 2 Mike1 8/25/06 9/15/06
> 3 Dinah 8/23/06 9/1/06
> 4 James 7/11/06 8/30/06
>
> The Query Should Return:
> ID CustomerID StartDate EndDate
> 1 Chuck1 9/1/06 9/30/06
> 4 James 7/11/06 8/30/06
>
> Thanks,
> Chuck
>sql
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