of values corresponding to the same date. I.e. for each date in column
"Date", I have a set of numbers in column "Numbers". However, I am
only interested in getting the largest value in column "Numbers"
corresponding to each value in column "Date". How do I do that?
Thanks,
Marcomdi00@.hotmail.com (Marco) wrote in news:e5f1d809.0411190312.c9f8b07
@.posting.google.com:
> My SELECT query returns a data set, one column of which contains a set
> of values corresponding to the same date. I.e. for each date in column
> "Date", I have a set of numbers in column "Numbers". However, I am
> only interested in getting the largest value in column "Numbers"
> corresponding to each value in column "Date". How do I do that?
> Thanks,
> Marco
SELECT "Date", MAX("Numbers")AS "Largest number"
FROM sometable
GROUP BY "Date"|||Marco wrote:
> My SELECT query returns a data set, one column of which contains a set
> of values corresponding to the same date. I.e. for each date in column
> "Date", I have a set of numbers in column "Numbers". However, I am
> only interested in getting the largest value in column "Numbers"
> corresponding to each value in column "Date". How do I do that?
> Thanks,
> Marco
Look up MAX and GROUP BY.
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