Help with reformatting xml

This is a simplistic example of what I’m trying to achieve;
I have some XML stored in a table (in a column of type xml):
<root>
<node id="1" somevalue="0" />
<node id="2" somevalue="1" />
<node id="3" somevalue="5" />
<node id="4" somevalue="7" />
</root>
And I want to generate new xml as follows:
<report>
<somevalue>13</somevalue>
</report>
Where 13 is the total value of all somevalue attributes.
I’ve been looking at the query() and nodes() methods and cannot quite do
what I want to do although I feel it might be possible. Currently I’m simply
selecting the xml and letting my client application do the formatting,
however I feel that this might cause some performance issues on large blobs
of xml data.
Is there a better way to do this?
Many thanks in advance for any help with this.
Julia Beresford.
Something like this?
DECLARE @.doc XML;
SELECT @.doc = N'<root>
<node id="1" somevalue="0" />
<node id="2" somevalue="1" />
<node id="3" somevalue="5" />
<node id="4" somevalue="7" />
</root>';
SELECT @.doc.query('<report>
<somevalue>
{ fn:sum(/root/node/@.somevalue) }
</somevalue>
</report>');
"Julia Beresford" <JuliaBeresford@.discussions.microsoft.com> wrote in
message news:5A5E83A9-F098-454D-80FA-FA212A3B15E8@.microsoft.com...
> This is a simplistic example of what I'm trying to achieve;
> I have some XML stored in a table (in a column of type xml):
> <root>
> <node id="1" somevalue="0" />
> <node id="2" somevalue="1" />
> <node id="3" somevalue="5" />
> <node id="4" somevalue="7" />
> </root>
> And I want to generate new xml as follows:
> <report>
> <somevalue>13</somevalue>
> </report>
> Where 13 is the total value of all somevalue attributes.
> I've been looking at the query() and nodes() methods and cannot quite do
> what I want to do although I feel it might be possible. Currently I'm
> simply
> selecting the xml and letting my client application do the formatting,
> however I feel that this might cause some performance issues on large
> blobs
> of xml data.
> Is there a better way to do this?
> Many thanks in advance for any help with this.
> Julia Beresford.
>