Help with query that only returns filds with certain characters

Hi,
I need to write a sql statement that only returns records if
a certain field DOESN'T contain a letter between a and d, a number, a #,
and a asterisk. If a different character is found there, it should
return that record.
For example. If we have these records
1. 43242#
2. %3499
3. $$#
4. ak
5. abd43#
6. 4242#44z
7. abc_
8. 342#ab*
9. *(
My query should return 2, 3, 4, 6, 7 and 9
I tried the following:
select * from Table1
where MyField LIKE '%[^0-9]%'
and MyField like '%[^a-d]%'
and it works fine for the numbers and letters, but I don't how to
include the # and the *
Thanks a lot.You can negate the LIKE clause by putting NOT in front of it.
So
SELECT * FROM Table1
WHERE MyField LIKE '%[^0-9]%'
AND MyField LIKE '%[^a-d]%'
AND MyField NOT LIKE '%#%'
AND MyField NOT LIKE '%*%'
One note though, the criteria you mentioned and the examples you gave do not
seem to match up.

But you said you should return rows (and your sample code that you said
works as intended) that do NOT contain a number. Some of those rows clearly
contain a number. Just not sure where you were going with that.
HTH,
John Scragg
"Star" wrote:
> Hi,
> I need to write a sql statement that only returns records if
> a certain field DOESN'T contain a letter between a and d, a number, a #,
> and a asterisk. If a different character is found there, it should
> return that record.
> For example. If we have these records
> 1. 43242#
> 2. %3499
> 3. $$#
> 4. ak
> 5. abd43#
> 6. 4242#44z
> 7. abc_
> 8. 342#ab*
> 9. *(
>
> My query should return 2, 3, 4, 6, 7 and 9
> I tried the following:
> select * from Table1
> where MyField LIKE '%[^0-9]%'
> and MyField like '%[^a-d]%'
> and it works fine for the numbers and letters, but I don't how to
> include the # and the *
> Thanks a lot.
>|||John,
Yes, I think my explanation was a little bit confusing.
I will try to rephrase it.
The query should return rows if the field
does not contain one of these characters:
- Numbers
- Letters (a-d)
- #
- *
For example, the query should return %3499 because
there is a % symbol there and that symbol is not on that list.
I had already tried what you suggested, but doesn't work for me.
If I run it, I wouldn't get 4242#44z back, and I should because it
contains a 'z'
John Scragg wrote:
> You can negate the LIKE clause by putting NOT in front of it.
> So
> SELECT * FROM Table1
> WHERE MyField LIKE '%[^0-9]%'
> AND MyField LIKE '%[^a-d]%'
> AND MyField NOT LIKE '%#%'
> AND MyField NOT LIKE '%*%'
> One note though, the criteria you mentioned and the examples you gave do n
ot
> seem to match up.
>
>
> But you said you should return rows (and your sample code that you said
> works as intended) that do NOT contain a number. Some of those rows clear
ly
> contain a number. Just not sure where you were going with that.
> HTH,
> John Scragg
>
> "Star" wrote:
>|||
You may also need to consider the escape character
e.g.
select * from (select 'a%b' col1 union select 'cde') x
where col1 LIKE '%\%%' ESCAPE ''
returns only 'a%b'|||Thanks, Steven. I will keep in mind.
However, I still haven't found a solution for this problem...
If I do this
select myfield from mytable
where myfield LIKE '%[^0-9]%'
and myfield like '%[^a-d]%'
and myfield not LIKE '%*%'
and myfield not LIKE '%#%'
and myfield LIKE '%\%%' ESCAPE ''
I only get %3499 back.
I really don't know what else to try...|||> I really don't know what else to try...
I've finally worked out (I think) what it is that you need
All records that contain one (or more) characters that are not in
(1234567890abcd#*)
Would that be a fair assumption ?|||
> I really don't know what else to try...
Is this SQL 2000 or SQL2005 ?
You could use a regex match
OR:
select col1 , patindex('%[^abcd1234567890#*]%',col1)
from
(
select
'43242#' col1
UNION SELECT
'%3499' UNION SELECT
'$$#' UNION SELECT
'ak' UNION SELECT
'abd43#' UNION SELECT
'4242#44z' UNION SELECT
'abc_' UNION SELECT
'342#ab*' UNION SELECT
'*('
) x
where patindex('%[^abcd1234567890#*]%',col1) <>0|||On Wed, 02 Nov 2005 14:05:46 -0500, Star wrote:

>John,
>Yes, I think my explanation was a little bit confusing.
>I will try to rephrase it.
>The query should return rows if the field
>does not contain one of these characters:
>- Numbers
>- Letters (a-d)
>- #
>- *
>For example, the query should return %3499 because
>there is a % symbol there and that symbol is not on that list.
Hi Star,
You write "does not contain one of these characters", but your example
suggests that you mean "contains at least one character not in this
list". For '%3499' does contain a number (even four!), yet you want it
returned.
SELECT MyField, other columns
FROM MyTable1
WHERE MyField LIKE '%[^0-9a-d#*]%'
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)|||Yes... I apologize again. I had a really bad day. I should have thought
twice my question.
Sorry about that and thanks for your help.|||Awesome!
That worked. To be honest, I didn't know about that patindex function. I
won't forget next time.
I really really appreciate your help and time.